Question

The resultant of two forces p and q is of magnitude p. if the force p is doubled , q remaining the same, then angle between new resultant and the force q is

Answer 1

tan inverse (2p/q)....

Answer 2

$\large\underline\mathrm\red{Given:-}$

• The resultant of two forces P and q is of magnitude p.

$\large\underline\mathrm\red{Solution}$

Let the resultant of P and Q.

R = √P² + Q² + 2PQ cos(theta)

$\large\underline\mathrm\red{Now}$, R = P

P = √P² + Q² + 2PQ cos(theta)

P² = P² + Q² + 2PQ cos(theta)

Q² + 2PQ cos(theta) = 0

Q + 2P cos(theta) = 0

$\large\underline\mathrm\red{Now}$, Required angle

β = tan^-1 [ p' / Q + 2P cos(theta)]

= tan^-1 (2P/0)

= tan^-1 (infinity) = 90°

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