the resultant of two perpendicular forces acting at a point is 15 n if one of the forces has magnitude of 12 n then the magnitude of the other force is
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Answer:
Let,
A = 12N
B = ?
Angle = x = 90 degrees
R = 15N
We know,
R = (A^2 + B^2 + 2ABCosx)^(0.5)
or, 15 × 15 = 12×12 + B^2 + 0 (Cos 90 = 0)
or, 225 = 144 + B^2
or, B^2 = 81
or, B = 9N
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Concept:
- Force
- Vector addition
- The process of adding two or more vectors together to create a vector sum is known as vector addition.
- Resolution of vectors
- Calculating the magnitude of a resultant vector
Given:
- Resultant force Fr = 15 N
- The first force component F₁ = 12 N
- The two force components are perpendicular to each other
Find:
- The second force component F₂
Solution:
For 2 perpendicular vectors, we find the resultant vector in the following manner
Resultant = √X²+Y²
Fr = √F₁²+F₂²
Fr² = F₁²+F₂²
Fr = 15 N, F₁ = 12 N
15² = 12²+F₂²
225 = 144 + F₂²
F₂² = 225 - 144
F₂² = 81
F₂ = 9
The other force has a magnitude of 9 N.
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