Question

The resultant of two unequal forces acting at 1500 is perpendicular to the smaller force. If

the larger force is 3N, find the smaller force and resultant.​

Answer 1

Answer:

From, the diagram you can tell the other force (magnitude B) must be act at 150

o

clockwise from A (i.e. 60

o

clock wide from the x−axis).

You can draw a vector adding triangle from A+B.R, but using components.

In the X− direction:

B.cos(60

o

)=10

Since cos(60

o

)=1.2

B(1.2)=10

B=

1.2

10

∴ B20 kg wt

In the y−direction:

A=B(sin60

o

)

Since sin60

o

3/2

A=20×

3

/2

A=10.

3

kgs wt

∴ 10

3

is smaller than 20.

So, the answer is 10

3

kgs wt.