the resultant of two vector of magnitude 2A and √2 A acting at angle theta is √10 A Find value of theta
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Answered by
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Given conditions,
Resultant (R) = √10 A
Magnitude of 2 vectors = 2A and √2 A
Using the Formula, for two vectors P and Q,
R² = P² + Q² + 2PQ Cosθ
⇒ 10A² = 4A² + 2A² + 2A × √2A Cosθ
⇒ 10A² = 6A² + 2√2 A Cosθ
∴ 2√2 A² Cosθ = 4A²
Cosθ = √2
Therefore, θ = Cos⁻¹(√2)
Hope it helps.
Answered by
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