Physics, asked by sfurtijain29, 10 months ago

the resultant of two vectors is perpendicular to one of them and has the magnitude 4m if the sum of the magnitude of two vectors is 8m then ​

Answers

Answered by phy1234
52

Answer:

this is the answer

Explanation:

given

 \alpha  = 90

Attachments:
Answered by amitnrw
107

Answer:

Magnitude of two vector = 3 & 5

Explanation:

the resultant of two vectors is perpendicular to one of them and has the magnitude 4m if the sum of the magnitude of two vectors is 8m then ​

Let say two vectors are A & B

and resultant Vector = C

To simplify Let say

A =  Xi   => Magnitude of Vector A = X

Then resultant Vector C =  4j  m

Perpendicular to one of vector with magnitude 4m

Vector B = Vector C  - Vector A

=> B =  4j - Xi

Magnitude of B = √(4² + X²)

sum of the magnitude of two vectors is 8m

=> X + √(4² + X²) = 8

=> √(16 + X²)  = 8 - X

Squaring both sides

16 + X² = 64 + X² - 16X

=> 16X = 48

=> X = 3

Vector A = 3i   => Magnitude = 3

Vector B = -3i + 4j  => Magnitude = √(-3)² + 4² = 5

Vector C = 4j

Magnitude of two vector = 3 & 5

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