The resultant of two vectors of magnitudes 2A and √2 A
acting at an angle ois √10 A. The correct value of 0 is :
(a) 30°
(b)45°
(d) 90°
(0)60°
Answers
Answered by
2
Explanation:
B 45 it is tan 45 so there the option b
Answered by
5
Answer:B) is right ans
Explanation:
R=√10A and two vectors are 2A and √2A
So
R²=p²+q²+2pq cos theta
(√10A)²= (2A)²+(√2A) ²+2×2A×√2A cos theta
10A²= 6A²+4√2A²cos theta
10A²-6A²= 4√2A²cos theta
4A²/4√2A²= cos theta
Cos theta=1/√2= 45°
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