Question

The resultant of two vectors P and Q is 10 . If P is 6 then what may be the value of Q ?​

Answer 1

Explanation:

The angle between will be 0°.

If resultant is P-Q, then angle would be 180°

Formula is R² = P² + Q² - 2PQCos(theta)

R is resultant; theta is angle between P & Q; R,P,Q are in Mod value.

(P+Q)² = P² + Q² - 2PQCos(theta)

P² + Q² + 2PQ = P² + Q² - 2PQCos(theta)

2PQ = 2PQCos(theta)

Cos(theta) = 1

Cos(theta) = Cos0°

theta = 0°