The resultant of u and v is perpendicular to u and has a magnitude equal to half of the magnitude of v.The angle between u and v is
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According to the question:
(u+v).u=0 (1)
|(u+v)|=|v|2 −(2)
Now, |u+v|=u2+v2+2uvcosθ−−−−−−−−−−−−−−√ −(3)[Parallelogram Law]
And from (1), we have:
u2+uvcosθ=0 −(4)
From (2) & (3)
v2+uvcosθ−−−−−−−−−√=v2
⟹cosθ=−3v/u
Also from (4) we have - cosθ=−u/v
Therefore, cosθ=−34×−1cosθ
⟹θ=cos−1(3/4−−−√)
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