The resultant of vector A and B is perpendicular to vector A what is the angle between A and B
Anonymous:
i think its 90 degree
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resultant of A and B is perpendicular upon A
so, dot product of A and ( A + B) = 0
e.g A.( A + B ) = 0
A² + A.B = 0
A² + | A | | B | cos∅ = 0
cos∅ = - |A| |A| /|A| |B| = -| A | /| B |
∅ = cos^-( -|A| /|B| )
so, dot product of A and ( A + B) = 0
e.g A.( A + B ) = 0
A² + A.B = 0
A² + | A | | B | cos∅ = 0
cos∅ = - |A| |A| /|A| |B| = -| A | /| B |
∅ = cos^-( -|A| /|B| )
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