Question

the resultant of vector p and q is perpendicular to vector p what is the angle between vector p and q​

Answer 1

Answer:

Correct option is

D

cos−1(−P/Q)

tanα=P+QcosθQsinθ

where α= angle made by R$ with vecP

θ= angle between P and Q

Here, α=90o,tanα=tan90o=∞

∴P+Qcosθ=0

cosθ=Q−P

θ=cos−1(Q−P)