The resultant of vectors OA and OB is perpendicular to OA (figure 2-W5) Find the angle AOB .
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Answer:
∠AOB = 131.8°
Explanation:
The resultant of vectors OA and OB is perpendicular to OA
Resultant = OA + OB
let say x = i & y = j
OA = 4 i + 0j
OB = 6Cosθ i + 6Sinθj
OA + OB = 4 i + 0j + 6Cosθ i + 6Sinθj
=> OA + OB = (4 + 6Cosθ)i + 6Sinθj
Now OA + OB ⊥ OA
=> OA + OB have only j component
=> 4 + 6Cosθ = 0
=> 2 + 3Cosθ = 0
=> Cosθ = -2/3
=> θ = 131.8°
∠AOB = 131.8°
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