The resultant to two Vectors A and B is R when vector A is reserved and again added to B the resultant turns through 90° .find the relation between A and B
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Answer:
Explanation:
=> Suppose angle between them is θ and resultant of both angle R₁ make angle α with B
So, tan(α) = Asin(θ)/B + A cos (θ) ...(1)
=> direction of A get reversed
here, angle between B and reversed A vector is (180⁰ - θ).
=> Suppose new resultant R₂ make angle β with B.
tan(β) = A sin (180⁰-θ)/B + A cos (180⁰-θ) = Asin(θ)/B-Acos(θ) ...(2)
=> As per the question, α + β =90⁰
tan(α + β) = tan(90⁰)
tan(α) + tan(β) = tan (90⁰)
tan(α) + tan(β) / 1 - tan(α) * tan(β) = 1/0
tan(α) * tan(β) = 1
Placing the values from (1) and (2)
( Asin(θ) /B+Acos(θ)) ( Asin(θ)/ B-Acos(θ)) = 1
A^2 sin^2θ = B^2 - A^2 cos^2 θ
A^2 (sin^2θ + cos^2θ) = B^2
A^2 = B^2
A = B
Thus, the relation between the two vectors A and B is 'A=B'.
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