Question

The reverse saturation current at 300K of a pn junction Ge diode is 5µA. Find the voltage to be applied across the junction to obtain a forward current of 50mA.

Answer 1

Answer:

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Answer 2

Step by Step explanation:

Given:

To find:

For the calculation of Voltage,

We know that Saturated Current $I_{s} = 10$∪$A$

∴ the potential barrier for germanium diode is,

⇒ $R=10$ × $10^{-6}$

⇒ $10^{-5}A$

⇒$R=0.3$

We know that $V=R(I+I_{s)}$, where '$I$' is voltage.

Thus,

⇒ $V= 0.3[(100$ × $10^{-3} ) + 10^{-9}]$

⇒ $0.3 [ \frac{1}{10}$ × $\frac{1}{10} ]$

⇒ $V=0.3$

Substitution values and finding Voltage,

⇒$1$ × $10^{-2} = 0.3 (I+10^{-5})$

⇒ $I=-10^{-5} + \frac{10^{-3} }{0.3}$

⇒ $I=0.33$

The voltage is $0.33$.