Chemistry, asked by arithabll, 1 month ago

The reversible reaction ;
2S02 + O2 =
2S03
has come to equilibrium
in a vessel of specific volume at
given temperature, Bofore the reaction begun
concentrato
ractants were
0.060mol/L SO2 and 0.050mol/L 02

After equilibrium
reached the concentration of S03 is
0,040mol/L

calculate
the equilibrium constant of Oxygen ​

Answers

Answered by anjupundir6530
0

Answer:

The reversible reaction ;

2S02 + O2 =

2S03

has come to equilibrium

in a vessel of specific volume at

given temperature, Bofore the reaction begun

concentrato

ractants were

0.060mol/L SO2 and 0.050mol/L 02

After equilibrium

reached the concentration of S03 is

0,040mol/L

calculate

the equilibrium

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