the reversible reaction so2 +no2(g) <-------> so3(g) + no(g) -------------(1)
takes place in 2 reversible steps with equlibrium constant 2.0 and 0.45 respectively
SO2+1/2O2 <---------->so3 , k=2.0------------(2)
NO2 <------------>NO+1/2O2 k=0.45---------- (3)
the equilibrium constant kc for the reaction (1) is
1) 0.9
2) 0.225
3) 4.44
4) 1/9
Answers
Answer:
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The reaction is SO2(g)+NO2(g)⇔SO3(g)+NO(g)...(1)
It is obtained by adding the following two reactions:
SO2(g)+21O2(g)⇋SO3(g),K1=2.0...(2)
NO2(g)⇋NO(g)+21O2(g),K2=0.45...(3)
The value of the equilibrium constant of reaction (1) is obtained by multiplying the values of the equilibrium constants of the reactions (2) and (3).
Thus, K=K1×K2=2.0×0.45=0.9.