Question

the rifle of mass 3 kg for A bullet of mass 0.03 kg the Bulla leaves the pair of the rifle at the velocity of 100 metre per second if the bullet is 0.005 seconds to move through it better than calculate the four Express by the rifle due to the recoil​

Answer 1

Answer:

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Step-by-step explanation:

Force experienced = 1000 N approximately.

Explanation:

We have,

Mass of the rifle, m₂ = 3 kg

Mass of the Bullet, m₁ = 0.03 kg

The velocity of the bullet, v₁ = 100 m/s

Time taken by bullet to move through the barrel, t = 0.003 s

So,

Initial velocity of rifle, u₂ = 0 m/s.

Initial velocity of bullet, u₁ = 0 m/s.

Final velocity of bullet, v₁ = 100 m/s.

Final velocity of rifle = v₂ m/s.

Now, we know from the law of conservation of momentum,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

So,

(0.03 x 0) + (3 x 0) = (0.03 x 100) + (3 x v₂)

0 = 3 + 3.v₂

v₂ = -1 m/s

Therefore, acceleration of the rifle is given by,

a=\frac{v-u}{t}a=

t

v−u

So,

\begin{gathered}a=\frac{-1-0}{0.003}\\a=-333.33\,m/s^{2}\end{gathered}

a=

0.003

−1−0

a=−333.33m/s

2

The Force experienced by rifle, therefore, would be,

F = m.a

F = 3.(-333.33)

F ≈ 1000 N