Question

the rifle of mass 3 kg for A bullet of mass 0.03 kg the Bulla leaves the pair of the rifle at the velocity of 100 metre per second if the bullet is 0.005 seconds to move through it better than calculate the four Express by the rifle due to the recoil​

Answer 1

Answer:

For bullet : m1= 0.03 kg, u1= 0, v1= 100 m/s

* For rifle: m2= 3 kg, u2= 0, v2=?

Sol. :- By conservation of momentum,

m1u1 + m2u2 = m1v1 + m2v2

= 0 + 0 = 0.03 × 100 + 3 × v2

or v2 = - 0.03 × 100/ 3

= -1 m/s

[Negative sign indicates that the rifle moves in a direction opposite to that of the bullet.]

Force exerted on the rifle,

F= m2 [v2 - u2/t]

= 3 [-1-0/0.003]

= - 1000 N . Ans.

[Negative sign indicates the force of recoil (backward kick) of the gun].tep-by-step explanation: