the right angle triangles abc, 8cm,15cm and 17cm are the lengnghts of ab,bc and ca respectively .then ,find out sina, cosa and tan a .
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in this base= 8, perpedicular= 15 and hypotaneous= 17
sin a= 15/17 as sin a=perpendicular/hypotaneous
cos a= 8/17 as cos a= base/ hypotaneous
tan a= 15/8 as tan a= perpedicular / base
sin a= 15/17 as sin a=perpendicular/hypotaneous
cos a= 8/17 as cos a= base/ hypotaneous
tan a= 15/8 as tan a= perpedicular / base
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Ac = 17 cm
Ab = 8 cm
BC = 15 cm
Sin a = perpendicular \ hypotenuse
= 8cm\ 17 cm
Cos a= base \ hypotenuse
= 15 cm \17 cm
Tan a = perpendicular \ base
= 8cm\ 15 cm
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