Question

The RMS(root mean Square) speed of certain gas at 27°C is 3x10^4 cm/sec. The temperature in °C(degree celcius) at which the velocity will be 6x10^4 cm/sec ? (in degree)​

Answer 1

Answer:

1200 K or 927°C

Explanation:

V rms= (3RT/M)^1/2

R = universal gas constant

T= temperature in kelvin

M = Molar mass of given gas

From this equation, we can understand that

rms speed is directly proportional to square root of temperature.

therefore, taking ratio of both,

(3×10^4)/(6×10^4) = (300/T)^1/2

(here mass is constant since the gas is same)

1/2 = (300/T)^1/2 . on squaring both sides,

1/4 = 300/T

T = 300× 4= 1200K (927°C)

Hope this helps you...thankyou