The RMS(root mean Square) speed of certain gas at 27°C is 3x10^4 cm/sec. The temperature in °C(degree celcius) at which the velocity will be 6x10^4 cm/sec ? (in degree)
Answers
Answered by
2
Answer:
1200 K or 927°C
Explanation:
V rms= (3RT/M)^1/2
R = universal gas constant
T= temperature in kelvin
M = Molar mass of given gas
From this equation, we can understand that
rms speed is directly proportional to square root of temperature.
therefore, taking ratio of both,
(3×10^4)/(6×10^4) = (300/T)^1/2
(here mass is constant since the gas is same)
1/2 = (300/T)^1/2 . on squaring both sides,
1/4 = 300/T
T = 300× 4= 1200K (927°C)
Hope this helps you...thankyou
Similar questions