Question

the rms speed of hydrogen gas molecules at 27°C is v. the rms speed of oxygen gas molecules at 927°C will be
(1) v/√2
(2) 2v
(3) v/2
(4) v/4​

Answer 1

Answer:

RMS = sqrt (3)(R)(T)/(M)

R = ideal gas constant = 8.3145 (kg·m2/sec2)/K·mol

T = absolute temperature in Kelvin

M = mass of a mole of the gas in kilograms.

RMS = sqrt (3)(8.314)(300)/0.032 = sqrt 239.4

RMS = 15.5 m/s

Explanation:

Answer 2

Answer:

v/2

EXPLANATION..

you know Vrms =

$\sqrt{3rt \div m}$

thus

for H2 { t= 273+27=300}

$\sqrt{3r300 \div m}$

and for O2 {t=927+273=1200}

$\sqrt{3r1200 \div m}$

we equalised them

thank you.