the rms speed of the molecules of a gas in a vessel is 400ms^-1.If half of the gas leaks out at constant temperature ,the rms speed of the remaining molecules will be
a.800ms^-1
b.400
.
c.400ms^-1
d.200ms^-1
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Answer:
Explanation:
Given,
v
rms
=400m/s
The RMS speed of the molecules will be
v
rms
=
M
3RT
. . . . . .(1)
where R= universal gas constant
T= temperature
M= molecular weight
The RMS speed does not depend on the quantity of the gas. For a given gas and the temperature, it remains constant.
So, the RMS speed of the remaining molecules is 400m/s.
The correct option is C.
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