The rms value of alternator is 200V and rms current delivered towards is 3A and phase angle between them is π/6. Find the power delivered.
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Heya
we know that
Power = E₀ × I₀ cosФ/2 { where Ф is called phase difference between voltage and current .
and we know that E₀/√2 and I₀/√2 = Er.m.s and I r.m.s { where E and I are peak values of voltage and current respectively .
so we can write it as
P = Er.m.s × I r.m.s cosФ
so now just plug the given values
you will get
P = 200 × 3 × cosπ/6
=> 600 × √3/2
=> 300√3 Watt
so power = 300√3 Watt.
#cosmic
we know that
Power = E₀ × I₀ cosФ/2 { where Ф is called phase difference between voltage and current .
and we know that E₀/√2 and I₀/√2 = Er.m.s and I r.m.s { where E and I are peak values of voltage and current respectively .
so we can write it as
P = Er.m.s × I r.m.s cosФ
so now just plug the given values
you will get
P = 200 × 3 × cosπ/6
=> 600 × √3/2
=> 300√3 Watt
so power = 300√3 Watt.
#cosmic
Avni05:
thank u
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