Question

The rms value of an ac of 50Hz is 10A. The time taken by an alternating current in reaching from 0 to maximum value and the peak value of the current will be​

Answer 1

Answer:

answer : 5 × 10⁻³ sec and 14.14 Amp

explanation : given , frequency, f = 50Hz

so, time period , T = 1/50 = 2 × 10^-2 sec

rms value of current of an ac circuit , i_{rms}irms = 10 Amp

we know, alternating current reaches the maximum value when time taken by it is one fourth of time period.

e.g., t=\frac{T}{4}t=4T

or, t = 2 × 10^-2/4 = 5 × 10^-3 sec

now, peak value of current, i_p=\sqrt{2}i_{rms}ip=2irms

here given, i_{peak}=\sqrt{2}\times10=14.14ipeak=2×10=14.14

hence, peak value of current will be 14.14Amp

Hope it helped.

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