Question

The rms velocity of gas molecules of a given amount of a gas at 27°C and 1.0*10^5 N/m² pressure is 200 m/sec. Of temperature and pressure are respectively 127°Cand 0.5*10^5N/m², the rms velocity will be

Answer 1

Answer:

Given that,

Vrms1=200m/s

T1=300k

T2=400k

Vrms2=?

We know that,

Vrms=√3RT/M

From this, vrms is directly proportional to the√T....

Now, vrms1/vrms2=√T1/√T2

200/vrms2=√300/√400

200/vrms2=√3/√4

200/vrms2=√3/2

√3vrms2=400

Vrms2=400/√3m/s

Explanation:

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