Question

The road at a circular turn of radius 10m is banked by an angle of 10°. The speed with which the
vehicle must move on the turn so that the normal contact force is able to provide the necessary
centripetal force is

Answer 1

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please refer to the attachment given below

V= sq root of rg . tan (10)

V= sq root of rg . tan (10)= sq root of 10 * 10 * tan (10)

V= sq root of rg . tan (10)= sq root of 10 * 10 * tan (10)= 5.57 m/s

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Answer 2

Answer:

$hey \: hope \: it \: helps \: you$

The road at a circular turn of radius 10m is banked by an angle of 10 degree.

The speed used by the vehicle to move on the turn so that the normal contact force is able to provide the necessary centripetal force is 5.57 m/s.

V= sq root of rg . tan (10)

= sq root of 10 * 10 * tan (10)

= 5.57 m/s