Question

the roaster from of set S = {x/x^2 = x, x belongs to R} is​

Answer 1

Answer:

As we know, 

x2+x−12=0

⇒x2+4x−3x−12=0

⇒x(x+4)−3(x+4)=0

⇒(x−3)(x+4)=0

x−3=0or x+4=0

x=3or x=−4

So, in

J={x:x∈R and x2+x−12=0}

J={−4,3}

Answer 2

Answer:

here is your answer

Step-by-step explanation:

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