Physics, asked by vineetjakhar5432100, 23 hours ago

The rod is made from two segments: AB is steel, and BC is brass. It is fixed at its ends and subjected to a torque of T = 680 N · m. If the steel portion has a diameter of 30 mm, determine the required diameter of the brass portion so the reactions at the walls will be the same. Take Gst = 75 GPa, Gbr = 39 GPa

Answers

Answered by shubhampalav18
0

Answer:

MAKE ME AS A BRANILIST

Explanation:

5-88. A rod is made from two segments: AB is steel and BC is brass. It is fixed at its ends and subjected to a torque of T = 680 Nm. If the steel portion has a diameter of 30 mm, determine the required diameter of the brass portion so the reactions at the walls will be the same. Gst = 75 GPa, Gbr = 39 GPa. 5-89. Determine the absolute maximum shear stress in the shaft of Prob. 5–88. 1.60 m 680 N·m Probs. 5–88/89

Similar questions