The
rohom
Maximum number of students among
1001 pens and 910 pencile can be disabled
in such a way that each student gets same
number of pens and same number of
pereils, is :
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Question:
Find the maximum number of students among 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and pencils.
Answer:
Explanation:
The maximum number of students = HCF(1001,910)
Finding HCF(1001,910) using prime factorization method:
1001 = 7 x 11 x 13
910 = 2 x 5 x 7 x 13
HCF = 7 x 13
= 91
Finding HCF(1001,910) using Euclid's Division Lemma:
By EDL,
a = bq + r 0 ≤ r < b
1001 = (910 × 1) + 91
910 = (91 × 10) + 0
Therefore 91 students are required
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