Question

The roller 150 long has a diameter of 70cm to level a playground it take 750 complete revolution detemine the cost Of levelling the playground at the rate of 75 pause per sq. Meter

Answer 1

Answer:

area = 2× pi × r × h

= 2 × 22/7 × 35 × 150

= 44 × 5 × 150 = 33000 cm² × 750 revolution

so total area covered = 24750000

cost 0.75 per m² or 10000 cm²

so total cost = 24750000 × 0.75 / 10000

= 2475 × 0.75 = rs. 1856.25

Step-by-step explanation:

Answer 2

Answer:

Area of playground = 750 × CSA of roller

= 750 x 2 x 22x 35 x 150 =

7

750 x 33000 =

= 24750000 cm ^

=2 2475 m ^ 2

Cost of leveling

= 2475 x 0.75

Rs 1856.25