Question

The root mean square velocity of a gas is ‘C’. If pressure of gas is doubled at constant temperature, what will be the root mean square velocity of the gas sample

Answer 1

Answer:

hight velocity is the answer

Answer 2

Explanation:

As we knw that the velocity (either average or RMS or Most probable) of a gaseous molecule is directly proportional to the temperature and inversely proportional to the Molecular Mass of the gas.

RMS velocity= √(3RT/M)

 = √(3PV/M)

= √(3P/d) where “d”= density of the gas.

Hence Pressure of a gas is nothing to do with the velocity of the gas. Suppose if the pressure of a gas is increased, proportionally and, it's volume will decrease and PV = will be a constant at a particular temperature. Similarly with  increase in pressure ,the density of the gas ”d” will also increase  and at particular temperature P/d will be a constant.

However there is a difference between the average velocity and the RMS velocity.

If Average velocity=√(8RT/M)= c, then

RMS velocity

= √(8RT/πM) x √(3π/8) =√3π/8) x c

= √(3 x 3.14/8) x c

= 1.0854 c** Therefore the RMS velocity of the gas will be nearly 1.0854 times the average velocity.