Question

The root mean square velocity of a gas molecule at 27°c is 1365m/s .The gas is

Answer 1

given, T = 27° c = 300 k

R = 8.314 j / mol / k

Crms = 1365 m/s

we know that, Crms = { √( 3RT ) ÷ M }

M = ( Crms )^2 ÷ 3RT ( by putting of this value )

M = 249.007 g / mol

the gas is Cf ( periodic table by IUPAC )