Chemistry, asked by Tandeep7904, 1 year ago

The root mean square velocity of one mole of a monoatomic gas having molar mass M is ur.m.s.. The relation between the average kinetic energy (E) of the gas and ur.m.s. is
(a) u_{r.m.s} = \sqrt{\frac{3E}{2M}}
(b) u_{r.m.s} = \sqrt{\frac{2E}{3M}}
(c) u_{r.m.s} = \sqrt{\frac{2E}{M}}
(d) u_{r.m.s} = \sqrt{\frac{E}{3M}}

Answers

Answered by varun200516
0

option d is the answer for the question

Answered by Anonymous
0
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The root mean square velocity of one mole of a monoatomic gas having molar mass M is ur.m.s.. The relation between the average kinetic energy (E) of the gas and ur.m.s. is
(a) u_{r.m.s} = \sqrt{\frac{3E}{2M}}
(b) u_{r.m.s} = \sqrt{\frac{2E}{3M}}
(c) u_{r.m.s} = \sqrt{\frac{2E}{M}}
(d) u_{r.m.s} = \sqrt{\frac{E}{3M}}

→ [B]


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