the root of 8-7y=1 is y=1
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yes, when y=1 then the whole equation is zero
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y^2+7y-8=0
y^2 - 8y + 1y - 8=0
(y+1) • (y-8)=0
y=-1||y=8
y^2 - 8y + 1y - 8=0
(y+1) • (y-8)=0
y=-1||y=8
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