Question

the root of a quadratic equation y square - 16y + 63 =0 are? ​

Answer 1

Answer:

Step-by-step explanation:

y²-16 y+63=0

y²-7 y-9 y+63=0

y(y-7)-9(y-7)=0

(y-7)(y-9)=0

y=7,9 are roots of this equation

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Answer 2

Answer: The roots of the equation are 7 and 9

Step-by-step explanation:

$y^{2}$ - 16y + 63 = 0

y^{2} - 7y - 9y + 63 = 0

y (y - 7) - 9(y - 7) = 0

(y - 7)(y - 9)=0

y = 7 or 9