Question

the root of ax²+bx+c=0,a≠0 are real and unequal. what is the value of D​

Answer 1

Answer:

D= b²-4ac>0

Step-by-step explanation:

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Answer 2

Given,

An Algebraic equation, $ax^{2} +bx+c=0.$, a≠0.

The roots of this equation are real and unequal.

To Find

The Value of D in that case.

Solution,

We know Discriminant, D of any equation alike $ax^{2} +bx+c=0.$ is = $b^{2}- 4ac.$

If  $b^{2}- 4ac.$ $\geq$0 then only the equation can have real roots,

And if  $b^{2}- 4ac.$ then equation can have unequal roots.

So if and only if, D= $b^{2}- 4ac.$>0 then the roots of  $ax^{2} +bx+c=0.$ be real and unequal.

Hence, for having real and unequal roots the value of D should be >0.