Question

The root of each of the following quadratic equation are real and equal find k 3y^2+ky+12=0 ,kx (x-2 )+6=0​

Answer 1

Answer:

3y

2

+ky+12

b

2

−4ac=0

K

2

−144=0

K=±

144

k=±12

Answer 2

solution given in image