The root of equation 7x²+x-1=0
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Answer:
It is of the form ax^2+bx+c=0
Then from the formula
x= -b+√b^2-4ac/2a and
-b-√b^2-4ac/2a
So, x= -1+√(1)^2-4(7)(-1)/2(7)
and -1-√(1)^2-4(7)(-1)/2(7)
=>x= (-1+√29)/14 and (-1-√29)/14 are the roots
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