The root of equation x+3(x+1)=11is
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Answer:
x + 3(x+1) = 11
x + 3x + 3 = 11
4x + 3 = 11
4x = 11 - 3
4x = 8
x = 8÷4
x = 2
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x+3(x+1)=11
x square + x + 3x+3 = 11
x square +4x = 8
x (x + 4 )= 8
x = 8/x+4
x square = 8/4
x square = 2
x = under root 2 or 1.4141
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