Question

The root of equation x square + x - 3 x + 1 is equal to zero where is a constant

Answer 1

Answer: x=1

Step-by-step explanation:

$x^2 + (x - 3x) + 1 = 0$               ....[given]

$x^2 -2x +1 = 0\\x^2 -x -x +1 = 0\\x(x-1) -1 (x-1) = 0\\(x-1)(x-1)=0$

therefore this equation has only one root

$x-1=0\\=> x=1$

Answer 2

step by step solution

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