Question

the root of Q E x²+ 7x+ 13 = 0 are​

Answer 1

eq=x²+7x+13

x={-b±√(b²-4ac)}/2a

x={-7±√(7²-4×1×13)}/2

x={-7+√(49-52)}/2

x={-7±√-3}/2

x=(-7+√3)/2,x=(-7-√3)/2

Answer 2

hello freind here your answer