Question

The root of quadratic equation 9 x square + 7 x minus 2 is equals to zero

Answer 1

Answer:

x=2/9 , -1

Step-by-step explanation:

$\sqrt{9x^{2} +7x-2}$ = 0

9x²+7x-2=0

D = 49-4(9)(-2)

   = 49+72

   = 121

$\sqrt{d}$ = ±11

⇒x = -b ± $\sqrt{d$ /2a

⇒x = -7 ±11 / 18

⇒x = -18/18 , 4/18

⇒x=2/9 , -1