the root of quadratic equations ax^2 + bx = 0 are
a) 0,b/a. b) 0,b/a
c) b/a, -b/a. d) -b/a, -b/a
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Answer:
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Step-by-step explanation:
Given:
ax^2 + bx = 0
Solution:
Let p,q be the roots of this equation.
We know that, Sum of the roots, p+q = -b/a
And,Product of the roots, pq = c/a
a => coefficient of x^2 term
b => coefficient of x term
c => constant term
Here, p+q = -b/a
pq = 0 ( since there is no constant term in this equation, we take c=0)
=> p = 0
Sub p = 0 in p + q = -b/a
=> q = -b/a
The roots of the equation ax^2 +bx = 0 are 0,-b/a
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