Math, asked by Shameermd111, 13 days ago

the root of root 3x^+10x-8root3=0​

Answers

Answered by Anonymous
3

{\huge{\mathcal{\boxed{\red{answer}}}}}</p><p>

x

2

+10x−8

3

=0

3

x

2

+6x+4x−8

3

=0

3

x(x+2

3

)−4(x+2

3

)=0

(x+2

3

)(

3

x−4)=0

∴ x=−2

3

and x=

3

∴ We can see both roots are irrational

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Answered by yuktivora62
1

Answer:

p><p>

x

2

+10x−8

3

=0

3

x

2

+6x+4x−8

3

=0

3

x(x+2

3

)−4(x+2

3

)=0

(x+2

3

)(

3

x−4)=0

∴ x=−2

3

and x=

3

∴ We can see both roots are irrational

Step-by-step explanation:

p><p>

x

2

+10x−8

3

=0

3

x

2

+6x+4x−8

3

=0

3

x(x+2

3

)−4(x+2

3

)=0

(x+2

3

)(

3

x−4)=0

∴ x=−2

3

and x=

3

∴ We can see both roots are irrational

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