Math, asked by pammi31, 11 months ago

the root of ×square+×+1=0are

Answers

Answered by amitukilblogger
1

Hey mate, here is your solution.

Step-by-step explanation:

x²+x+1 = 0

x²+2.x.1/2+1/4 = 1/4-1

(x+1/2)² = -3/4

(x+1/2)² = {3(i)²/4}

(x+1/2) = ±(i/2).3^½

x = -½±(i/2).3^½

x = (-1±i.3^½)/2 .......Answer

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