the root of ×square+×+1=0are
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Hey mate, here is your solution.
Step-by-step explanation:
x²+x+1 = 0
x²+2.x.1/2+1/4 = 1/4-1
(x+1/2)² = -3/4
(x+1/2)² = {3(i)²/4}
(x+1/2) = ±(i/2).3^½
x = -½±(i/2).3^½
x = (-1±i.3^½)/2 .......Answer
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