Question

The root of the bi quadratic equation x4+x3−7x2−x+6=0x4+x3−7x2−x+6=0 that does not exceed -2 ​

Answer 1

Answer:

For example

Step-by-step explanation:

Given equation is x  4  −5x  3  +7x  2  −17x+11=0

Replacing x→x+2, we get

(x+2)  4  −5(x+2)  3  +7(x+2)  2  −17(x+2)+11=0

⇒(x+2)  2  (x+2)  2  −5(x+2)  3  +7(x  2  +4x+4)−17x−34+11=0

⇒x  4  +3x  3  +x  2  −17x−19=0