Question

The root of the equation 100p^2-20p+1 =0 are​

Answer 1

$100 {p}^{2} - 20p + 1 = 0 \\ ( - 10p + 1)( - 10p + 1) = 0 \\ \\ \\ - 10p + 1 = 0 \\ - 10p = - 1 \\ \frac{ - 10p}{ - 10} = \frac{ - 1}{ - 10} \\ p = \frac{1}{10}$

Answer 2

100p²–20p+1=0

100p²–10p–10p+1=0

10p(10p–1)–1(10p–1)=0

(10p–1)(10p–1)=0

(10–p)=0 or (10–p)=0

(10=p) or (10=p)