Question

the root of the equation 3(x+3)²=48 are​

Answer 1

Answer:

x is 1 and -7

Step-by-step explanation:

3(x+3)²=48

3(x² + 9 + 6x) = 48

x² + 9 + 6x = 48/3

x² + 6x + 9 = 16

x² + 6x + 9 - 16 = 0

x² + 6x -7 = 0

x² + 7x - x - 7 = 0

x(x + 7) -1(x + 7) = 0

(x - 1)(x + 7) = 0

x - 1 = 0       ; x + 7 = 0

x = 1         ; x = -7

Answer 2

Answer:

x = (-7) , 1

Step-by-step explanation:

$3 {(x + 3)}^{2} = 48 \\ \\3 ({(x)}^{2} + 2 \times x \times 3 + {3}^{2} ) = 48 \\ \\ 3( {x }^{2} + 6x + 9) = 48 \\ \\ 3 {x}^{2} + 18x + 27 = 48 \\ \\ 3 {x }^{2} + 18x + 27 - 48 = 0 \\ \\ 3 {x}^{2} + 18x - 21 = 0 \\ \\ 3( {x}^{2} + 6x - 7) = 0 \\ \\ {x }^{2} + 6x - 7 = 0 \\ \\ {x}^{2} + 7x - x - 7 = 0 \\ \\ )x(x + 7) - 1(x + 7) = 0 \\ \\ (x + 7)(x - 1) = 0 \\ \\ \\ (x + 7) = 0 \\ x = ( - 7) \\ \\ \\ (x - 1) = 0 \\ x = 1 \\ \\ x = ( - 7) \: and \: 1 \: \: (ans)$

please give me a lot of like