Question

The root of the equation 7x^2+ x-1=0 are real and distinct real and equal
not real
none of these

Answer 1

Answer:

Real and distinct.

Step-by-step explanation:

b^2 - 4ac = 1^2 - 4 (-1)(7)

                = 1 +28

                = 29.

Hence roots are real and distinct.

Hope this answer helps.

Please mark me as the brainliest....

Answer 2

Given : The quadratic equation is, 7x²+x-1 = 0

To find : The nature of the roots of the given quadratic equation.

Solution :

The roots are real and distinct.

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the nature of the roots)

First of all, we have to calculate the discriminant of the given quadratic equation.

Discriminant = b² - 4ac

Comparing the given quadratic equation, with ax²+bx+c = 0, we get :

• a = 7
• b = 1
• c = -1

So, the value of discriminant will be :

= (1)² - {4 × 7 × (-1)}

= 1 - (-28)

= 1 + 28

= 29

Now, discriminant is obviously greater than zero. (29>0)

Which means the roots will be real and distinct.

(this will be considered as the final result)

Hence, the roots of the equation 7x²+x-1 = 0 are real and distinct.