the root of the equation | x^2-x-6 | = x+2 are
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mod is there so we will get 2 equations
x^2-x-6=x+2 and x^2-x-6=-x-2
Solving first equation
x^2-2x-8=0
x^2-4x+2x-8=0
(x+2)(x-4)=0
x=-2
x=4
Similarly solve equation 2
we get x= 2
x=-2
x^2-x-6=x+2 and x^2-x-6=-x-2
Solving first equation
x^2-2x-8=0
x^2-4x+2x-8=0
(x+2)(x-4)=0
x=-2
x=4
Similarly solve equation 2
we get x= 2
x=-2
Sid234:
tHnkEww bro☺️
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