Question

The root of the equation x2 - 3x - m (m + 3) = 0 where m is a constant, are

Answer 1

Answer: x = -m and x = m + 3

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Step-by-step explanation:

$x^{2} -3x-m(m+3)=0$

$x^{2} -m^{2} -3m-3x\\(x-m)(x+m)-3(x+m)\\(x+m)(x-m-3)\\x=-m\\x=m+3$